c program to reverse a number

1#include <stdio.h>
2int main() {
3    int n, rev = 0, remainder;
4    printf("Enter an integer: ");
5    scanf("%d", &n);
6    while (n != 0) {
7        remainder = n % 10;
8        rev = rev * 10 + remainder;
9        n /= 10;
10    }
11    printf("Reversed number = %d", rev);
12    return 0;
13}

1#include <stdio.h>
2int main() {
3    int n, rev = 0, remainder;
4    printf("Enter an integer: ");
5    scanf("%d", &n);
6    while (n != 0) {
7        remainder = n % 10;
8        rev = rev * 10 + remainder;
9        n /= 10;
10    }
11    printf("Reversed number = %d", rev);
12    return 0;
13}
14
15

1void printReverse(int n) {
2  if (n < 1) return;
3  cout << n << endl;
4  printReverse(n - 1);
5}
6
7printReverse(10);  /// 10 9 8 7 6 5 4 3 2 1

1#include <stdio.h>
2int main() {
3    int n, rev = 0, remainder;
4    printf("Enter an integer: ");
5    scanf("%d", &n);
6    while (n != 0) {
7        remainder = n % 10;
8        rev = rev * 10 + remainder;
9        n /= 10;
10    }
11    printf("Reversed number = %d", rev);
12    return 0;
13}
14