count vowels in a string javascript

1const vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'];
2
3function countVowels(sentence) {
4  let counts = 0;
5  for(let i = 0; i < vowels.length; i++) {
6    if(vowels.includes(sentence[i])) {
7      counts++;
8    }
9  }
10  return console.log(counts);
11}
12
13countVowels('Hello World');
14countVowels('AaEeIiOoUu');
15countVowels('aaaaa');

1const vowelCount = str => {
2  let vowels = /[aeiou]/gi;
3  let result = str.match(vowels);
4  let count = result.length;
5
6  console.log(count);
7};

1function getCount(str) {
2  return (str.match(/[aeiou]/ig)||[]).length;
3}

1function countVowels(str) {
2  return str.match(/[aeiou]/g).length;
3}

1function getCount(str) {
2let vowelList = 'AEIOUaeiou'
3let vowelsCount = 0;
4
5 for(var i = 0; i < str.length ; i++)
6  {
7    if (vowelList.indexOf(str[i]) !== -1)
8    {
9      vowelsCount += 1;
10    }
11  }
12  return vowelsCount;
13}
14

1// BEST and FASTER implementation using regex
2const countVowels = (str) => (str.match(/[aeiou]/gi) || []).length