datediff in seconds in pandas

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showing results for - "datediff in seconds in pandas"
Lorenzo
18 Mar 2017
1t1 = pd.to_datetime('1/1/2015 01:00')
2t2 = pd.to_datetime('1/1/2015 03:30')
3
4print pd.Timedelta(t2 - t1).seconds / 3600.0
5
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