fetch url in javascript

1fetch('https://api.github.com/users/kipngetich33')
2  .then(response => response.json())
3  .then(formatedResponse =>  console.log(formatedResponse))
4//NB please replace url with your own

1// GET Request.
2fetch('https://jsonplaceholder.typicode.com/users')
3    // Handle success
4    .then(response => response.json())  // convert to json
5    .then(json => console.log(json))    //print data to console
6    .catch(err => console.log('Request Failed', err)); // Catch errors

1const url = 'https://randomuser.me/api';
2// The data we are going to send in our request
3let data = {
4    name: 'Sara'
5}
6// The parameters we are gonna pass to the fetch function
7let fetchData = { 
8    method: 'POST', 
9    body: data,
10    headers: new Headers()
11}
12fetch(url, fetchData)
13.then(function() {
14    // Handle response you get from the server
15});

1fetch('http://example.com/movies.json')
2  .then((response) => {
3    return response.json();
4  })
5  .then((data) => {
6    console.log(data);
7  });
8

1fetch('/about').then(function (response) {
2	// The API call was successful!
3	return response.text();
4}).then(function (html) {
5
6	// Convert the HTML string into a document object
7	var parser = new DOMParser();
8	var doc = parser.parseFromString(html, 'text/html');
9
10	// Get the image file
11	var img = doc.querySelector('img');
12	console.log(img);
13
14}).catch(function (err) {
15	// There was an error
16	console.warn('Something went wrong.', err);
17});
18