1// For large data, it's better to use reduce. Supose arr has a large data in this case:
2const arr = [1, 5, 3, 5, 2];
3const max = arr.reduce((a, b) => { return Math.max(a, b) });
4
5// For arrays with relatively few elements you can use apply: 
6const max = Math.max.apply(null, arr);
7
8// or spread operator:
9const max = Math.max(...arr);
10

1var arr = [1, 2, 3];
2var max = arr.reduce(function(a, b) {
3  return Math.max(a, b);
4});

1function getMaxOfArray(numArray) {
2    return Math.max.apply(null, numArray);
3}

1const maxMinArray = (a,b,...c) =>{
2    //we are concatinating this array
3    let array = [a,b];
4    let newArray = array.concat(c);
5    //now let's get started with the excersice
6    let max = 0;
7    for(let number of newArray){
8        if(max<number){
9            max = number;
10        }
11    }
12    let min = max;
13    for(let number of newArray){
14        if(number<min){
15            min = number;
16        }
17    }
18    return console.log(max + ' ' + min)
19}
20//example: 
21maxMinArray(12,14,15,23)
22

1Math.max(10, 20);   //  20
2Math.max(-10, -20); // -10
3Math.max(-10, 20);  //  20
4