showing results for - "get param from url jquery"
Alessandra
18 Jan 2018
1function GetUrlParameter(sParam)
2
3{
4    var sPageURL = window.location.search.substring(1);
5
6    var sURLVariables = sPageURL.split('&');
7
8    for (var i = 0; i < sURLVariables.length; i++)
9    {
10        var sParameterName = sURLVariables[i].split('=');
11
12        if (sParameterName[0] == sParam)
13
14        {
15            return sParameterName[1];
16        }
17    }
18}
19
20And this is how you can use this function assuming the URL is,
21http://dummy.com/?technology=jquery&blog=jquerybyexample.
22
23var tech = GetUrlParameter('technology');
24var blog = GetUrlParameter('blog');
Manuela
12 Mar 2019
1var getUrlParameter = function getUrlParameter(sParam) {
2    var sPageURL = window.location.search.substring(1),
3        sURLVariables = sPageURL.split('&'),
4        sParameterName,
5        i;
6
7    for (i = 0; i < sURLVariables.length; i++) {
8        sParameterName = sURLVariables[i].split('=');
9
10        if (sParameterName[0] === sParam) {
11            return typeof sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
12        }
13    }
14    return false;
15};
16And this is how you can use this function assuming the URL is,
17http://dummy.com/?technology=jquery&blog=jquerybyexample.
18
19var tech = getUrlParameter('technology');
20var blog = getUrlParameter('blog');
Philipp
22 Feb 2016
1var getUrlParameter = function getUrlParameter(sParam) {
2    var sPageURL = window.location.search.substring(1),
3        sURLVariables = sPageURL.split('&'),
4        sParameterName,
5        i;
6
7    for (i = 0; i < sURLVariables.length; i++) {
8        sParameterName = sURLVariables[i].split('=');
9
10        if (sParameterName[0] === sParam) {
11            return typeof sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
12        }
13    }
14    return false;
15};
16
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