how does urllib parse urlsplit work in python

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Mara
13 Nov 2020
1>>> urllib.parse.urlparse("http://example.com/pa/th;param1=foo;param2=bar?name=val#frag")
2ParseResult(scheme='http', netloc='example.com', path='/pa/th', params='param1=foo;param2=bar', query='name=val', fragment='frag')
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