how to check if a number is armstrong in python

1num = 1634
2
3# Changed num variable to string, 
4# and calculated the length (number of digits)
5order = len(str(num))
6
7# initialize sum
8sum = 0
9
10# find the sum of the cube of each digit
11temp = num
12while temp > 0:
13   digit = temp % 10
14   sum += digit ** order
15   temp //= 10
16
17# display the result
18if num == sum:
19   print(num,"is an Armstrong number")
20else:
21   print(num,"is not an Armstrong number")
22

1# Python program to check if the number is an Armstrong number or not
2
3# take input from the user
4num = int(input("Enter a number: "))
5
6# initialize sum
7sum = 0
8
9# find the sum of the cube of each digit
10temp = num
11while temp > 0:
12   digit = temp % 10
13   sum += digit ** 3
14   temp //= 10
15
16# display the result
17if num == sum:
18   print(num,"is an Armstrong number")
19else:
20   print(num,"is not an Armstrong number")
21

1# Program to check Armstrong numbers in a certain interval
2
3lower = 100
4upper = 2000
5
6for num in range(lower, upper + 1):
7
8   # order of number
9   order = len(str(num))
10    
11   # initialize sum
12   sum = 0
13
14   temp = num
15   while temp > 0:
16       digit = temp % 10
17       sum += digit ** order
18       temp //= 10
19
20   if num == sum:
21       print(num)
22