how to print the elements of a linked list in c

1typedef struct node{
2    int value; //this is the value the node stores
3    struct node *next; //this is the node the current node points to. this is how the nodes link
4}node;
5
6void printList(node *head){
7    node *tmp = head;
8
9    while(tmp != NULL){
10        if(tmp->next == NULL){
11            printf("%d", tmp->value);
12        }
13        else{
14            printf("%d, ", tmp->value);
15        }
16        tmp = tmp->next;
17    }
18}