java scanner string nextline after nextint

1//The problem is with the input.nextInt() method - it only reads the int value. So when you continue reading with input.nextLine() you receive the "\n" Enter key. So to skip this you have to add the input.nextLine(). Hope this should be clear now.
2
3//Try it like that:
4
5System.out.print("Insert a number: ");
6int number = input.nextInt();
7input.nextLine(); // This line you have to add (It consumes the \n character)
8System.out.print("Text1: ");
9String text1 = input.nextLine();
10System.out.print("Text2: ");
11String text2 = input.nextLine();

1int option = input.nextInt();
2input.nextLine();  // Consume newline left-over
3String str1 = input.nextLine();