leap year algorithm

1def isLeapYear (year):
2    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
3		true
4    else:
5    	false

1if year % 4 == 0:
2  if year % 100 == 0:
3    if year % 400 == 0:
4      print("leap year")
5    else:
6      print("not a leap year")
7  else:
8    print("leap year")
9else:
10  print("not a leap year")