showing results for - "parse query url javascript"
Léopold
11 Jan 2017
1const urlParams = new URLSearchParams(window.location.search);
2const myParam = urlParams.get('myParam');
3
Edoardo
27 Sep 2018
1const getParameters = (URL) => {
2  URL = JSON.parse('{"' + decodeURI(URL.split("?")[1]).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g, '":"') +'"}');
3  return JSON.stringify(URL);
4};
5
6getParameters(window.location)
7// Result: { search : "easy", page : 3 }
8
Leona
17 Jul 2019
1function getQueryVariable(variable)
2{
3       var query = window.location.search.substring(1);
4       var vars = query.split("&");
5       for (var i=0;i<vars.length;i++) {
6               var pair = vars[i].split("=");
7               if(pair[0] == variable){return pair[1];}
8       }
9       return(false);
10}
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