1Variable is used to store value
2Pointer is used to store addresss of value

1/*
2**use of pointers is that here even if we change the value of c since the adderss is
3* of c is assigned to pc it *pc will also get modified*/
4int* pc, c;
5c = 5;
6pc = &c;
7*pc = 1;
8printf("%d", *pc);  // Ouptut: 1
9printf("%d", c);    // Output: 1
10

1As discussed earlier, 'p' is a pointer to 'a'. Since 'a' has a value of 10, so '*p' is 10. 'p' stores the address of a. So the output p = 0xffff377c implies that 0xffff377c is the address of 'a'. '&p' represents the address of 'p' which is 0xffff3778. Now, '*&p' is the value of '&p' and the value of '&p' is the address of 'a'. So, it is 0xffff377c.

1#include <iostream>
2
3float average(float a[])
4{
5    int i;
6    float avg, sum=0;
7    for(i=0;i<8;++i)
8    {
9        sum+= a[i];
10    }
11    avg = sum/8;
12    return avg;
13}
14
15int main(){
16	float b, n[ ] = { 20.6, 30.8, 5.1, 67.2, 23, 2.9, 4, 8 };
17	b = average(n);
18  	std:: cout << "Average of numbers = " << b << std::endl;
19	return 0;
20}
21

1Size of arr[] 24
2Size of ptr 4

1#include <iostream>
2// by using increment sign we know whole array
3int main()
4{
5	using namespace std;
6	int ar[] = { 1,2,3,4,5,6,7,8,9,10 };
7	for (int m : ar)
8	{
9		cout << m << endl;
10	}
11	return 0;
12}
13

1p = 0xffff377c
2*p = 10
3&p = 0xffff3778
4*&p = 0xffff377c