python if else list comprehension

1[statement if condition else statement for _ in iterable_object]
2#statement are without assignment

1l = [22, 13, 45, 50, 98, 69, 43, 44, 1]
2a = [x + 1 if x >= 45 else x + 5 for x in l]

1# Basic syntax for if:
2desired_elements = [f(x) for x in iterable_object if condition]
3
4# Basic syntax for if else:
5desired_elements = [f(x) if condition else g(x) for x in iterable_object]
6
7# Basic syntax for if elif else:
8desired_elements = [f(x) if condition elif condition_2 g(x) else h(x) for x in iterable_object]
9
10# Example usage:
11# Say you want to return the square of elements if elements are less 
12# than 10, otherwise you just want to return the elements themselves:
13your_list = [1, 7, 13, 11, 23, 2, 17, 42, 8, 5]
14new_list = [x**2 if x < 10 else x for x in your_list]
15print(new_list)
16--> [1, 49, 13, 11, 23, 4, 17, 42, 64, 25]

1[unicode(x.strip()) if x is not None else '' for x in row]