python sort the values in a dictionary

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Lorenzo
09 Jan 2017
1x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
2{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
3{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
source
Sami
30 Oct 2017
1from operator import itemgetter
2new_dict = sorted(data.items(), key=itemgetter(1))
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