return an rdd of grouped items

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1rdd = sc.parallelize([1, 1, 2, 3, 5, 8])
2result = rdd.groupBy(lambda x: x % 2).collect()
3sorted([(x, sorted(y)) for (x,y) in result])
4# [(0, [2, 8]), (1, [1, 1, 3, 5])]

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