setting a condition for perfect square in python

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Jerónimo
30 Jul 2020
1import math
2
3# Taking the input from user
4number = int(input("Enter the Number"))
5
6root = math.sqrt(number)
7if int(root + 0.5) ** 2 == number:
8    print(number, "is a perfect square")
9else:
10    print(number, "is not a perfect square")
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