sort object by value javascript

1let list = [
2  {
3      name: "world"
4  },
5  {
6      name: "hello",
7  },
8];
9
10// This doesn't account for if names are the same between objects
11let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));
12
13console.log(x);
14
15/*
16[
17  {
18      name: "hello",
19  },
20  {
21      name: "world"
22  },
23];
24*/

1var array = [
2  {name: "John", age: 34},
3  {name: "Peter", age: 54},
4  {name: "Jake", age: 25}
5];
6
7array.sort(function(a, b) {
8  return a.age - b.age;
9}); // Sort youngest first

1grossaryList = {
2  'bread': 1,
3  'apple': 6,
4  'milk': 1, 
5  'orange': 3,
6  'broccoli': 2 
7}
8
9return Object
10  .entries(grossaryList)
11  .sort((a,b) => b[1]-a[1])
12
13//=> [['apple', 6],['orange', 3],['broccoli', 2],['bread',1],['milk', 1]]

1const books = [
2  {id: 1, name: 'The Lord of the Rings'},
3  {id: 2, name: 'A Tale of Two Cities'},
4  {id: 3, name: 'Don Quixote'},
5  {id: 4, name: 'The Hobbit'}
6]
7
8compareObjects(object1, object2, key) {
9  const obj1 = object1[key].toUpperCase()
10  const obj2 = object2[key].toUpperCase()
11
12  if (obj1 < obj2) {
13    return -1
14  }
15  if (obj1 > obj2) {
16    return 1
17  }
18  return 0
19}
20
21books.sort((book1, book2) => {
22  return compareObjects(book1, book2, 'name')
23})
24
25// Result:
26// {id: 2, name: 'A Tale of Two Cities'}
27// {id: 3, name: 'Don Quixote'}
28// {id: 4, name: 'The Hobbit'}
29// {id: 1, name: 'The Lord of the Rings'}

1arr.sort((x, y) => x.distance - y.distance);

1let orders = [
2  { 
3    order: 'order 1', date: '2020/04/01_11:09:05'
4  },
5  { 
6    order: 'order 2', date: '2020/04/01_10:29:35'
7  },
8  { 
9    order: 'order 3', date: '2020/04/01_10:28:44'
10  }
11];
12
13
14console.log(orders);
15
16orders.sort(function(a, b){
17  let dateA = a.date.toLowerCase();
18  let dateB = b.date.toLowerCase();
19  if (dateA < dateB) 
20  {
21    return -1;
22  }    
23  else if (dateA > dateB)
24  {
25    return 1;
26  }   
27  return 0;
28});
29
30console.log(orders);