sort tuple list python

1a = [(5,8), (3,4), (9,7)]
2
3#sort by first element in tuple
4result = sorted(a, key=lambda tup: tup[0])
5
6#OR to do inplace sort:
7
8a.sorted(key = lambda tup: tup[0])
9
10# output
11[(3, 4), (5, 8), (9, 7)]
12

1sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])

1sorted_by_second = sorted(data, key=lambda tup: tup[1])
2

1# Python program to sort a list of tuples by the second Item 
2  
3# Function to sort the list of tuples by its second item 
4def Sort_Tuple(tup):
5    # Getting length of list of tuples
6    lst = len(tup)
7    for i in range(0, lst):
8        for j in range(0, lst-i-1):
9            if (tup[j][1] > tup[j + 1][1]):
10                temp = tup[j]
11                tup[j]= tup[j + 1]
12                tup[j + 1]= temp
13    return tup

1# If you have a tuple, first convert it to a list:
2
3a = (3,1,2)
4a = list(a)
5
6# And now you can just use the inbuilt function ( .sort() ):
7a.sort()
8print(a)
9>>> [1,2,3]
10
11# ^ by using .sort() you are modifying the original list / tuple, however
12# if you want to make a sorted copy of the list / tuple, then you use this:
13
14a = [3, 6, 8, 2, 78, 1, 23, 45, 9]
15print(sorted(a))
16
17>>> [1, 2, 3, 6, 8, 9, 23, 45, 78]
18
19# This also works with the alphabet or a combination between letters and
20# numbers.

1# To have largest first and smalest last
2sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1], reverse=True)