sorting array of numbers in javascript

1// Sort an array of numbers based on numerical value.
2let numbers = [23, 65, 88, 12, 45, 99, 2000]
3
4let sortednumbers = numbers.sort((a, b) => a - b);
5//=> [12, 23, 45, 65, 88, 99, 2000]

1var numArray = [140000, 104, 99];
2numArray.sort(function(a, b) {
3  return a - b;
4});
5
6console.log(numArray);

1
2        
3            
4        
5     let numbers = [0, 1, 2, 3, 10, 20, 30];
6numbers.sort((a, b) => a - b);
7
8console.log(numbers);

1var numArray = [140000, 104, 99];
2
3numArray.sort(function(a, b) {
4  return a - b;
5});
6
7// Array(3) [ 99, 104, 140000 ]

1function sortNumber(a, b) {
2  return a - b;
3}
4Arr.sort(sortNumber);

1var arr = [23, 34343, 1, 5, 90, 9]
2
3//using forEach
4var sortedArr = [];
5arr.forEach(x => {
6    if (sortedArr.length == 0)
7        sortedArr.push(x)
8    else {
9        if (sortedArr[0] > x) sortedArr.unshift(x)
10        else if (sortedArr[sortedArr.length - 1] < x) sortedArr.push(x)
11        else sortedArr.splice(sortedArr.filter(y => y < x).length, 0, x)
12    }
13})
14console.log(sortedArr);
15
16
17// using sort method
18console.log(arr.sort((a,b)=>{
19    return a-b;
20}));
21