sum the digits of an integer

1function digSum(n) {
2    let sum = 0;
3    let str = n.toString();
4    console.log(parseInt(str.substring(0, 1)));
5    for (let i = 0; i < str.length; i++) {
6        sum += parseInt(str.substring(i,i+1));
7        
8    }
9    return sum;
10}

1num = [int(d) for d in input("Enter the Number:")]
2sum = 0
3for i in range(0, len(num)):
4    sum = sum + num[i]
5
6print("Sum of Digits of a Number: {}".format(sum))
7
8# This code is contributed by Shubhanshu Arya (Prepinsta Placement Cell Student) 

1def getSum(n)
2  n.digits.sum
3end
4
5print "Sum of digits = ", getSum(555);

1#include <stdio.h>
2 
3int getSum(unsigned long long n) {
4    int sum = 0;
5    for (; n; n /= 10)
6    	sum += n % 10;
7    return sum;
8}
9
10int main(){
11	printf("Sum of digits = %d\n", getSum(555));
12}