unique numbers in array java

1int [] arr = {1,1,1,2,2,2,3,3,3,4,4,5,5,6,7,8,};
2
3for (int j= 0; j < arr.length; j++){
4int count1 = 0; // to find out how many time value is appeared in the arry
5for (int i = 0; i < arr.length; i++){
6     if(arr[i] == arr[j] ) {    
7    // if(arr[i] == 1 ) { once boyleydi ikinci for gelince soldaki oldu
8      count1++; // arraydeki harfleri tek tek saymak icin
9  }
10 }
11    if(count1 == 1 ){
12    System.out.print(arr[j]+" ");// 6 7 8 uniqe
13 }

1import java.util.ArrayList;
2
3public class UniqueNumbersInArray {
4
5    public static void main(String[] args) {
6
7
8    int arr[] = { 4,5,5,4,5,6,5,8,4,7};
9
10        ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
11        for (int i = 0; i < arr.length; i++) {
12
13            int k = 0;
14            if (!uniqueArr.contains(arr[i])){
15                uniqueArr.add(arr[i]);
16                k++;
17
18                for (int j = i; j < args.length ; j++) {
19                    if (arr[i]==arr[j]){
20                        k++;
21                    }
22                }
23
24                System.out.println(arr[i]);
25                System.out.println(k);
26            }
27
28        }
29    }
30}