dijkstra 27s algorithm

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Jannik
18 Jan 2019
1#include<bits/stdc++.h>
2using namespace std;
3
4int main()
5{
6	int n = 9;
7	
8	int mat[9][9] = { { 100,4,100,100,100,100,100,8,100}, 
9                      { 4,100,8,100,100,100,100,11,100}, 
10                      {100,8,100,7,100,4,100,100,2}, 
11                      {100,100,7,100,9,14,100,100,100}, 
12                      {100,100,100,9,100,100,100,100,100}, 
13                      {100,100,4,14,10,100,2,100,100}, 
14                      {100,100,100,100,100,2,100,1,6}, 
15                      {8,11,100,100,100,100,1,100,7}, 
16                      {100,100,2,100,100,100,6,7,100}};
17	
18	int src = 0;
19	int count = 1;
20	
21	int path[n];
22	for(int i=0;i<n;i++)
23		path[i] = mat[src][i];
24	
25	int visited[n] = {0};
26	visited[src] = 1;
27	
28	while(count<n)
29	{
30		int minNode;
31		int minVal = 100;
32		
33		for(int i=0;i<n;i++)
34			if(visited[i] == 0 && path[i]<minVal)
35			{
36				minVal = path[i];
37				minNode = i;
38			}
39		
40		visited[minNode] = 1;
41		
42		for(int i=0;i<n;i++)
43			if(visited[i] == 0)
44				path[i] = min(path[i],minVal+mat[minNode][i]);
45					
46		count++;
47	}
48	
49	path[src] = 0;
50	for(int i=0;i<n;i++)
51		cout<<src<<" -> "<<path[i]<<endl;
52	
53	return(0);
54}
Emir
19 Sep 2017
1//Dijkstra's Algorithm (Using priority queue)
2//Watch Striver graph series on youtube I learned from there
3#include<bits/stdc++.h>
4using namespace std;
5void addedge(vector<pair<int,int>>adj[],int u,int v,int w)
6{
7    adj[u].push_back(make_pair(v,w));
8    adj[v].push_back(make_pair(u,w));
9}
10void Dijkstra(vector<pair<int,int>>adj[],int source,int n)
11{
12    priority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> prior; //Min-Heap storing will store distance and node
13    vector<int>dist(n,INT_MAX);
14    dist[source]=0;
15    prior.push(make_pair(0,source));
16    while(!prior.empty())
17    {
18        int distance=prior.top().first;
19        int node=prior.top().second;
20        prior.pop();
21        for(auto it:adj[node])
22        {
23            int next_node=it.first;
24            int next_weight=it.second;
25            if(dist[next_node]>distance+next_weight)
26            {
27                dist[next_node]=dist[node]+next_weight;
28                prior.push(make_pair(dist[next_node],next_node));
29            }
30        }
31    }
32    for(int i=0;i<n;i++)
33    {
34        cout<<dist[i]<<" ";
35    }
36}
37int main()
38{
39    int vertex,edges;
40    cout<<"ENTER THE NUMBER OF VERTEX AND EDGES:"<<endl;
41    cin>>vertex>>edges;
42    vector<pair<int,int>>adj[vertex];
43    int a,b,w;
44    cout<<"ENTER THE LINK AND THEN WEIGHT:"<<endl;
45    for(int i=0;i<edges;i++)
46    {
47        cin>>a>>b>>w;
48        addedge(adj,a,b,w);
49    }
50    int source;
51    cout<<"ENTER THE SOURCE NODE FROM WHICH YOU WANT TO CALCULATE THE SHORTEST DISTANCE:"<<endl;
52    cin>>source;
53    Dijkstra(adj,source,vertex);
54    return 0;
55}
56
Élise
08 May 2020
1#include <limits.h> 
2#include <stdio.h> 
3  
4
5#define V 9 
6  
7
8int minDistance(int dist[], bool sptSet[]) 
9{ 
10
11    int min = INT_MAX, min_index; 
12  
13    for (int v = 0; v < V; v++) 
14        if (sptSet[v] == false && dist[v] <= min) 
15            min = dist[v], min_index = v; 
16  
17    return min_index; 
18} 
19  
20
21void printSolution(int dist[]) 
22{ 
23    printf("Vertex \t\t Distance from Source\n"); 
24    for (int i = 0; i < V; i++) 
25        printf("%d \t\t %d\n", i, dist[i]); 
26} 
27  
28
29void dijkstra(int graph[V][V], int src) 
30{ 
31    int dist[V]; 
32    
33  
34    bool sptSet[V];
35 
36    for (int i = 0; i < V; i++) 
37        dist[i] = INT_MAX, sptSet[i] = false; 
38  
39  
40    dist[src] = 0; 
41  
42  
43    for (int count = 0; count < V - 1; count++) { 
44       
45        int u = minDistance(dist, sptSet); 
46  
47       
48        sptSet[u] = true; 
49  
50       
51        for (int v = 0; v < V; v++) 
52  
53           
54            if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX 
55                && dist[u] + graph[u][v] < dist[v]) 
56                dist[v] = dist[u] + graph[u][v]; 
57    } 
58  
59 
60    printSolution(dist); 
61} 
62  
63
64int main() 
65{ 
66    
67    int graph[V][V] = { { 0, 4, 0, 0, 0, 0, 0, 8, 0 }, 
68                        { 4, 0, 8, 0, 0, 0, 0, 11, 0 }, 
69                        { 0, 8, 0, 7, 0, 4, 0, 0, 2 }, 
70                        { 0, 0, 7, 0, 9, 14, 0, 0, 0 }, 
71                        { 0, 0, 0, 9, 0, 10, 0, 0, 0 }, 
72                        { 0, 0, 4, 14, 10, 0, 2, 0, 0 }, 
73                        { 0, 0, 0, 0, 0, 2, 0, 1, 6 }, 
74                        { 8, 11, 0, 0, 0, 0, 1, 0, 7 }, 
75                        { 0, 0, 2, 0, 0, 0, 6, 7, 0 } }; 
76  
77    dijkstra(graph, 0); 
78  
79    return 0; 
80} 
Emy
15 Nov 2019
1//djikstra's algorithm using a weighted graph (STL)
2//code by Soumyadepp
3//insta: @soumyadepp
4//linkedinID: https://www.linkedin.com/in/soumyadeep-ghosh-90a1951b6/
5
6#include <bits/stdc++.h>
7#define ll long long
8using namespace std;
9
10//to find the closest unvisited vertex from the source
11//note that numbering of vertices starts from 1 here. Calculate accordingly
12ll minDist(ll dist[], ll n, bool visited[])
13{
14    ll min = INT_MAX;
15    ll minIndex = 0;
16    for (ll i = 1; i <= n; i++)
17    {
18        if (!visited[i] && dist[i] <= min)
19        {
20            min = dist[i];
21            minIndex = i;
22        }
23    }
24    return minIndex;
25}
26
27//djikstra's algorithm for single source shortest path
28void djikstra(vector<pair<ll, ll>> *g, ll n, ll src)
29{
30    bool visited[n + 1];
31    ll dist[n + 1];
32    for (ll i = 0; i <= n; i++)
33    {
34        dist[i] = INT_MAX;
35        visited[i] = false;
36    }
37
38    dist[src] = 0;
39
40    for (ll i = 0; i < n - 1; i++)
41    {
42        ll u = minDist(dist, n, visited);
43        visited[u] = true;
44        for (ll v = 0; v < g[u].size(); v++)
45        {
46            if (dist[u] + g[u][v].second < dist[g[u][v].first])
47            {
48                dist[g[u][v].first] = dist[u] + g[u][v].second;
49            }
50        }
51    }
52    cout << "VERTEX : DISTANCE" << endl;
53    for (ll i = 1; i <= n; i++)
54    {
55        if (dist[i] != INT_MAX)
56            cout << i << "         " << dist[i] << endl;
57        else
58            cout << i << "         "
59                 << "not reachable" << endl;
60    }
61    cout << endl;
62}
63
64int main()
65{
66    //to store the adjacency list which also contains the weight
67    vector<pair<ll, ll>> *graph;
68    ll n, e, x, y, w, src;
69    cout << "Enter number of vertices and edges in the graph" << endl;
70    cin >> n >> e;
71    graph = new vector<pair<ll, ll>>[n + 1];
72    cout << "Enter edges and weight" << endl;
73    for (ll i = 0; i < e; i++)
74    {
75        cin >> x >> y >> w;
76        //checking for invalid edges and negative weights.
77        if (x <= 0 || y <= 0 || w <= 0)
78        {
79            cout << "Invalid parameters. Exiting" << endl;
80            exit(-1);
81        }
82        graph[x].push_back(make_pair(y, w));
83        graph[y].push_back(make_pair(x, w));
84    }
85    cout << "Enter source from which you want to find shortest paths" << endl;
86    cin >> src;
87    if (src >= 1 && src <= n)
88        djikstra(graph, n, src);
89    else
90        cout << "Please enter a valid vertex as the source" << endl;
91    return 0;
92}
93
94//time complexity : O(ElogV)
95//space complexity: O(V)
96
Nohlan
09 Nov 2020
1
2# Providing the graph
3n = int(input("Enter the number of vertices of the graph"))
4
5# using adjacency matrix representation 
6vertices = [[0, 0, 1, 1, 0, 0, 0],
7            [0, 0, 1, 0, 0, 1, 0],
8            [1, 1, 0, 1, 1, 0, 0],
9            [1, 0, 1, 0, 0, 0, 1],
10            [0, 0, 1, 0, 0, 1, 0],
11            [0, 1, 0, 0, 1, 0, 1],
12            [0, 0, 0, 1, 0, 1, 0]]
13
14edges = [[0, 0, 1, 2, 0, 0, 0],
15         [0, 0, 2, 0, 0, 3, 0],
16         [1, 2, 0, 1, 3, 0, 0],
17         [2, 0, 1, 0, 0, 0, 1],
18         [0, 0, 3, 0, 0, 2, 0],
19         [0, 3, 0, 0, 2, 0, 1],
20         [0, 0, 0, 1, 0, 1, 0]]
21
22# Find which vertex is to be visited next
23def to_be_visited():
24    global visited_and_distance
25    v = -10
26    for index in range(num_of_vertices):
27        if visited_and_distance[index][0] == 0 \
28            and (v < 0 or visited_and_distance[index][1] <=
29                 visited_and_distance[v][1]):
30            v = index
31    return v
32
33
34num_of_vertices = len(vertices[0])
35
36visited_and_distance = [[0, 0]]
37for i in range(num_of_vertices-1):
38    visited_and_distance.append([0, sys.maxsize])
39
40for vertex in range(num_of_vertices):
41
42    # Find next vertex to be visited
43    to_visit = to_be_visited()
44    for neighbor_index in range(num_of_vertices):
45
46        # Updating new distances
47        if vertices[to_visit][neighbor_index] == 1 and 
48                visited_and_distance[neighbor_index][0] == 0:
49            new_distance = visited_and_distance[to_visit][1] 
50                + edges[to_visit][neighbor_index]
51            if visited_and_distance[neighbor_index][1] > new_distance:
52                visited_and_distance[neighbor_index][1] = new_distance
53        
54        visited_and_distance[to_visit][0] = 1
55
56i = 0
57
58# Printing the distance
59for distance in visited_and_distance:
60    print("Distance of ", chr(ord('a') + i),
61          " from source vertex: ", distance[1])
62    i = i + 1
Chevy
21 Oct 2018
1function Dijkstra(Graph, source):
2       dist[source]  := 0                     // Distance from source to source is set to 0
3       for each vertex v in Graph:            // Initializations
4           if vsource
5               dist[v]  := infinity           // Unknown distance function from source to each node set to infinity
6           add v to Q                         // All nodes initially in Q
7
8      while Q is not empty:                  // The main loop
9          v := vertex in Q with min dist[v]  // In the first run-through, this vertex is the source node
10          remove v from Q 
11
12          for each neighbor u of v:           // where neighbor u has not yet been removed from Q.
13              alt := dist[v] + length(v, u)
14              if alt < dist[u]:               // A shorter path to u has been found
15                  dist[u]  := alt            // Update distance of u 
16
17      return dist[]
18  end function
19
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