getting leap year in python

1def is_leap(year):
2   return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

1year = int(input("Write any year to check if it is leap year:- "))
2if year % 4 == 0:
3  if year % 100 == 0:
4    if year % 400 == 0:
5      print("Leap year.")
6    else:
7      print("Not leap year.")
8  else:
9    print("Leap year.")
10else:
11  print("Not leap year.")